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L & D Series from cyberoro (1D~4D) problem #35
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Author:  Magicwand [ Mon Sep 13, 2010 12:57 am ]
Post subject:  L & D Series from cyberoro (1D~4D) problem #35

BLACK TO LIVE.
Click Here To Show Diagram Code
[go]$$Bcm1 Prisoners: W=0, B=0
$$ -----------------------------
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . , . . . . . , O O . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . O X X . |
$$ | . . . . . . . . . O . . . |
$$ | . . . . . . . . . O . . . |
$$ | . . . , . . . . . , X X . |
$$ | . . . . . . . . O . O X . |
$$ | . . . . . . . . . . O O . |
$$ | . . . . . . . . . . . . . |
$$ ----------------------------[/go]

Author:  Loons [ Mon Sep 13, 2010 2:12 am ]
Post subject:  Re: L & D Series from cyberoro (1D~4D) problem #35

I don't see a way to refute black :b1: . It makes one eye solidly, and the other stones have so many liberties I can't see anything for white to try.
Click Here To Show Diagram Code
[go]$$Bcm1 Prisoners: W=0, B=0
$$ -----------------------------
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . , . . . . . , O O . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . O X X . |
$$ | . . . . . . . . . O . . 1 |
$$ | . . . . . . . . . O 5 4 . |
$$ | . . . , . . . . . , X X 3 |
$$ | . . . . . . . . O . O X 2 |
$$ | . . . . . . . . . . O O . |
$$ | . . . . . . . . . . . . . |
$$ ----------------------------[/go]


Edit: This was the first move for me to consider, becoming sure enough to post it took about 30 seconds. I'm going to feel dumb if I'm wrong ^^

Author:  Marcus [ Mon Sep 13, 2010 5:10 am ]
Post subject:  Re: L & D Series from cyberoro (1D~4D) problem #35

Click Here To Show Diagram Code
[go]$$Bcm1 Prisoners: W=0, B=0
$$ -----------------------------
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . , . . . . . , O O . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . O X X . |
$$ | . . . . . . . . . O . . 1 |
$$ | . . . . . . . . . O . . . |
$$ | . . . , . . . . . , X X . |
$$ | . . . . . . . . O . O X . |
$$ | . . . . . . . . . . O O . |
$$ | . . . . . . . . . . . . . |
$$ ----------------------------[/go]


Seems simple enough. I can't find anything to refute it.

Click Here To Show Diagram Code
[go]$$Bcm1 Eyes at a and one of b
$$ -----------------------------
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . , . . . . . , O O . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . O X X a |
$$ | . . . . . . . . . O . b 1 |
$$ | . . . . . . . . . O . . b |
$$ | . . . , . . . . . , X X . |
$$ | . . . . . . . . O . O X . |
$$ | . . . . . . . . . . O O . |
$$ | . . . . . . . . . . . . . |
$$ ----------------------------[/go]


I don't see how White can attack this effectively. Best effort I get is this:

Click Here To Show Diagram Code
[go]$$Bcm1 Black still lives.
$$ -----------------------------
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . . . . . . . . . . . |
$$ | . . . , . . . . . , O O . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . . O X . |
$$ | . . . . . . . . . O X X . |
$$ | . . . . . . . . . O 3 . 1 |
$$ | . . . . . . . . . O . . . |
$$ | . . . , . . . . . , X X . |
$$ | . . . . . . . . O . O X 2 |
$$ | . . . . . . . . . . O O . |
$$ | . . . . . . . . . . . . . |
$$ ----------------------------[/go]

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