move d is not the best and not the worst of (a,b,d)
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| Endgame position and miai value analysis http://www.lifein19x19.com/viewtopic.php?f=15&t=19184 |
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| Author: | Knotwilg [ Tue Jun 06, 2023 6:13 am ] |
| Post subject: | Endgame position and miai value analysis |
I'm taking this position from an AI Sensei discussion. I'd like to get anyone's idea on what's the biggest endgame move: A or B? In particular I'd like to get expert opinion on the miai values. Here's my analysis: |
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| Author: | Gomoto [ Tue Jun 06, 2023 9:50 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
| Author: | Knotwilg [ Tue Jun 06, 2023 11:39 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
It's really an endgame question. Not "what's the most secure way to carry the 20+ lead into victory" |
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| Author: | Gomoto [ Tue Jun 06, 2023 12:28 pm ] |
| Post subject: | Re: Endgame position and miai value analysis |
move d is not the best and not the worst of (a,b,d) |
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| Author: | dany [ Wed Jun 07, 2023 7:29 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Knotwilg wrote: I'm taking this position from an AI Sensei discussion. I'd like to get anyone's idea on what's the biggest endgame move: A or B? In particular I'd like to get expert opinion on the miai values. Here's my analysis: A miai value is about 2.8 B miai value is 1.92 https://senseis.xmp.net/?MiaiValuesList ... o199#toc16 Knotwilg wrote: By miai value analysis A is bigger than B. But when I verify that by playing out the board, Black B seems to give a result that's 1 point better. C plays a role: it's also ambiguous, being a 2 point move with a 2 point follow-up. No, B is 1 point worse. White 4 move from A sequence is a mistake |
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| Author: | Knotwilg [ Wed Jun 07, 2023 12:58 pm ] |
| Post subject: | Re: Endgame position and miai value analysis |
OK so B is 1.92 or 1+11/12 which is well documented. Let me then try getting to your 2.8 for A, reducing the diagram to the local position and taking a little of the complexity out (perhaps affecting the value you got) This branch is easy: we can assume A and B as boundaries since the hanes cancel out. The net result (count) is 4. this is also easy for the same reason. The count is 1. Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 So we have, with value and (count) 2.25 (1.75) / \ 1.5(-0.5) (4) / \ (-2)(1) The value of A is 2.25 and the count is 1.75 Could it be that your 2.8 is a rounding of 2.75 and that you have mistakenly calculated the average between the value 1.5 and the count 4? I think it's more likely that you are the expert and I made a mistake. Please correct! |
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| Author: | dany [ Thu Jun 08, 2023 3:20 pm ] |
| Post subject: | Re: Endgame position and miai value analysis |
Knotwilg wrote: Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 In similar positions b > a. It is easy to verify this by constructing https://senseis.xmp.net/?DifferenceGame So black or white play b instead of a And in the current position white b is sente Knotwilg wrote: So we have, with value and (count) 2.25 (1.75) / \ 1.5(-0.5) (4) / \ (-2)(1) The value of A is 2.25 and the count is 1.75 Could it be that your 2.8 is a rounding of 2.75 and that you have mistakenly calculated the average between the value 1.5 and the count 4? I think it's more likely that you are the expert and I made a mistake. Please correct! I'm definitely not an expert and I don't fully understand how all this counts. But after reading the articles https://senseis.xmp.net/?MiaiCountingWithTrees and https://senseis.xmp.net/?MiaiValuesList%2FDiscussion (especially the section "For instance, suppose that you start with this tree"), something cleared up and now I understand the calculation process better. After White 1, the temperature has increased. Therefore it's sente and Black has to answer 2. So A miai value is (4+1)/2 = 2.5 |
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| Author: | Knotwilg [ Fri Jun 09, 2023 7:30 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Thanks a lot! But still not sure: how does the temperature increase? Let me explain the tree in words: The count of Black first is 4 The count of White first is -0.5, because next White going first the count is -2 and Black going first the count is 1; (-2+1)/2=-0.5 Therefore the value of the second move is 1.5 (moving the count from -0.5 to either -2 or 1) The count of the original position is (4-0.5)/2 = 1.75 Therefore the value of the first move is 2.25 (moving the count to either 4 or -0.5) The value of the first move (2.25) is larger than the value of the second move (1.5) So the temperature decreases and the move is gote. |
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| Author: | dany [ Fri Jun 09, 2023 9:17 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Knotwilg wrote: But still not sure: how does the temperature increase? Maybe we are talking about different "temperatures". Mine from https://senseis.xmp.net/?MiaiCountingWithTrees. Temperature = (blackcount-Whitecount)/(blacktally-whitetally) And calc from bottom to top. Follow the algorithm from https://senseis.xmp.net/?MiaiValuesList%2FDiscussion (the section "For instance, suppose that you start with this tree"). 1) build a tree of moves assuming all moves are gote 2) check that the temperature in the tree decreases from top to bottom 3) if at some node constraint 2) is violated, then the tree of moves (and values) is inconsistent and this move is sente 4) if 3) then "cut" branches and recalc values and temperatures. make the tree consistent |
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| Author: | Knotwilg [ Sat Jun 10, 2023 3:12 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
dany wrote: Knotwilg wrote: But still not sure: how does the temperature increase? Maybe we are talking about different "temperatures". Mine from https://senseis.xmp.net/?MiaiCountingWithTrees. Temperature = (blackcount-Whitecount)/(blacktally-whitetally) And calc from bottom to top. Follow the algorithm from https://senseis.xmp.net/?MiaiValuesList%2FDiscussion (the section "For instance, suppose that you start with this tree"). 1) build a tree of moves assuming all moves are gote 2) check that the temperature in the tree decreases from top to bottom 3) if at some node constraint 2) is violated, then the tree of moves (and values) is inconsistent and this move is sente 4) if 3) then "cut" branches and recalc values and temperatures. make the tree consistent Hehe I'm under the - possibly false - belief that is exactly what I did ...
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| Author: | lightvector [ Sat Jun 10, 2023 11:35 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Knotwilg wrote: Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 I'm skeptical of this, unless this is intended to be an approximation rather than to be exactly accurate? Playing A and B here are not independently 50-50able, because playing A may affect the liberties that determine whether B is sente atari on the whole group, and vice versa whoever plays B first affects the value of the situation at A. Additionally, if we completely ignore black's possible liberty shortage from B and just focus on the shape at A by itself, this is not a situation where you can take the average of 3 and 2 points for white. This is because if black plays A first and white blocks, that itself is already a slight local gain and the temperature drops, leaving a remaining ko mouth where black can tenuki. (See the fifth diagram on the 0.67 section at https://senseis.xmp.net/?MiaiValuesList%2F000To099#toc7, "Make ko"). The value of this resulting ko mouth position has a 1/3 in it, so if you don't end up with a factor of 3 in the denominator finally after doing the full calculation, something may be off. For an accurate evaluation of the miai value, rather than just an approximation, due to these details you may need to expand the tree out a bit further. (And in the process, determine actually what the correct first move for each side is here!) |
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| Author: | Knotwilg [ Tue Jun 13, 2023 3:52 pm ] |
| Post subject: | Re: Endgame position and miai value analysis |
lightvector wrote: Knotwilg wrote: Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 I'm skeptical of this, unless this is intended to be an approximation rather than to be exactly accurate? Playing A and B here are not independently 50-50able, because playing A may affect the liberties that determine whether B is sente atari on the whole group, and vice versa whoever plays B first affects the value of the situation at A. Additionally, if we completely ignore black's possible liberty shortage from B and just focus on the shape at A by itself, this is not a situation where you can take the average of 3 and 2 points for white. This is because if black plays A first and white blocks, that itself is already a slight local gain and the temperature drops, leaving a remaining ko mouth where black can tenuki. (See the fifth diagram on the 0.67 section at https://senseis.xmp.net/?MiaiValuesList%2F000To099#toc7, "Make ko"). The value of this resulting ko mouth position has a 1/3 in it, so if you don't end up with a factor of 3 in the denominator finally after doing the full calculation, something may be off. For an accurate evaluation of the miai value, rather than just an approximation, due to these details you may need to expand the tree out a bit further. (And in the process, determine actually what the correct first move for each side is here!) Thanks I gave it a try here: https://senseis.xmp.net/?BQM606 |
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| Author: | Schachus [ Wed Jun 14, 2023 4:53 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
In the diagram undertitled WWBW, imo white 5 should be destroying the eye at a instead of blocking the side, which also protects the side at the same time, because of blacks damezumari. This is also the reason why imo black 4 should also be making the eye at a instead of a hane on the side) |
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| Author: | Knotwilg [ Wed Jun 14, 2023 7:38 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Schachus wrote: In the diagram undertitled WWBW, imo white 5 should be destroying the eye at a instead of blocking the side, which also protects the side at the same time, because of blacks damezumari. This is also the reason why imo black 4 should also be making the eye at a instead of a hane on the side) Thanks for spotting it. I changed accordingly. |
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| Author: | dany [ Wed Jun 14, 2023 7:40 am ] |
| Post subject: | Re: Endgame position and miai value analysis |
Schachus wrote: In the diagram undertitled WWBW, imo white 5 should be destroying the eye at a instead of blocking the side, which also protects the side at the same time, because of blacks damezumari. This is also the reason why imo black 4 should also be making the eye at a instead of a hane on the side) Yes dany wrote: Knotwilg wrote: Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 In similar positions b > a. It is easy to verify this by constructing https://senseis.xmp.net/?DifferenceGame So black or white play b instead of a |
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| Author: | Knotwilg [ Wed Jun 14, 2023 12:35 pm ] |
| Post subject: | Re: Endgame position and miai value analysis |
dany wrote: Schachus wrote: In the diagram undertitled WWBW, imo white 5 should be destroying the eye at a instead of blocking the side, which also protects the side at the same time, because of blacks damezumari. This is also the reason why imo black 4 should also be making the eye at a instead of a hane on the side) Yes dany wrote: Knotwilg wrote: Here I'm giving both 1/2 a chance to play A, so for White to make 3 points instead of 2, and also 1/2 a chance to play B, so for Black to make 1 point instead of 0. On average, the count is -2 In similar positions b > a. It is easy to verify this by constructing https://senseis.xmp.net/?DifferenceGame So black or white play b instead of a Indeed. I have adapted it accordingly in the page. |
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