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L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 5:52 pm
by Magicwand
Black to play. it is easy if you are know famous tesuji.
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 6:19 pm
by Jordus
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0I know that
kills white before white can kill the black group at H6... but seeing that this is a 1D-4D problem, I am probably missing some deep overall strategy....
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 6:22 pm
by Redundant
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0Instantly knew this was
http://senseis.xmp.net/?PattingTheRaccoonsBelly . If white four is anywhere else, black captures white.
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 6:39 pm
by Magicwand
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 6:45 pm
by Shaddy
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 6:50 pm
by Redundant
Try number 2:
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0Or
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 7:40 pm
by jts
redundant, can't w win the semeai instead?
my own stab...
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0edit: so neither of these is w's strongest resistance, shaddy gives a better one.
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Mon Sep 20, 2010 7:50 pm
by Shaddy
jts wrote: redundant, can't w win the semeai instead?
my own stab...
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0edit: so neither of these is w's strongest resistance, shaddy gives a better one.
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0first diagram: 3 at 5
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Tue Sep 21, 2010 1:10 pm
by Magicwand
Shaddy wrote: My best attempt
cutting at 1 will fail because of this.
$$Wcm10 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Wcm10 Prisoners: W=0, B=0
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Wed Sep 22, 2010 11:29 am
by Violence
Here goes.
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0
Re: L & D Series from cyberoro (1D~4D) problem #215
Posted: Wed Sep 22, 2010 2:18 pm
by Loons
After 5 frustratingly puzzled minutes I came up with this. Move 1 looks like a good candidate for being a famous tesuji. Does it have a name ? Am I just embarrassing myself again ?
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0and white has no good 6. White can try other moves but black just plays the move that keeps him ahead in the capturing race.
Edit: This seems much stiffer resistance for white
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0But once again white seems to have no good 6.
Aaaand why I'm inevitably wrong:
$$Bcm1 Prisoners: W=0, B=0
Click Here To Show Diagram Code [go]$$Bcm1 Prisoners: W=0, B=0I think the answer starts at a instead, and is similar to my answer.
kills white before white can kill the black group at H6... but seeing that this is a 1D-4D problem, I am probably missing some deep overall strategy....