RobertJasiek wrote:
asura, for your Japanese rules model, start testing the second part of the official commentary, except examples 16-18. All the other examples must work as shown. Besides, test snapback at a territory boundary and further fake dead stones on the inside / outside.
I said I tested it on a (relative) small number, but of corse I tested it on the examples of the official commentary, else I had said I tested it not at all

BTW my model works for example 16-18, too, as my motivation was to get a model that ALWAYS works correct. (Of corse I mean the *intended* result, not the flaw with endless ko-passes.)
Of corse (as far I'm aware) it covers snapback and dead stones on the inside, too. What exactly do you mean with "fake" dead stones?
And even a unfilled ko (capturable-3 in j2003) works without introducing a more complex method.
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Do you want to replace local-2 by something else? Why? Recall the equivalence relation to two-eye-formation:
http://home.snafu.de/jasiek/wagcmod.htmlI'm neither using different local-n's nor using 2-eye-formation. Only can (force) capture or cannot (force) capture matters. Depending on this every string gets exactly one of two states: dead or alive. This is more easy than in j2003. The most difficult is to restrict the area where a new played compensation stone affects the state of the string in question.
This point makes a different with this rules.
Quote:
Japanese / Korean locality: the complexity is not the same, but the complexity class is the same: first define "force", then define life and death and locality concepts by using force. (My Simplified Japanese Rules and Simplified Korean Rules forgo such and rely on much simpler, implicit localities.)
I dont't see why you think that your model can prove that the complexity class is the same. That would require to prove that your model is the one with the lowest complexity for both rules.
Lets say my model for j1989 is less complex than j2003 but it doesn't work for the "Korean" rules then the reverse would be proven.
edit: Actually this wouldn't prove the reverse, because for this I would need to prove my model is the one with lowest complextity for j1989.