daal wrote:What is the
easiest way to determine a rough value of a move in order to compare alternatives. I am more interested in "ballpark" than "correct." For starters, how about this: black to play: What are a, b and c worth?
$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . a . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . b . . |
$$ | . . , X . . , . . |
$$ | . . . . c O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+
- Click Here To Show Diagram Code
[go]$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . a . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . b . . |
$$ | . . , X . . , . . |
$$ | . . . . c O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+[/go]
Hi Daal,
A first easy rule is to play first the moves that are
very sente, then the reverse sente, then the double gote.
To know if a move is sente, you have to look where the sequence can stop. For example :
$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . . . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . a b . |
$$ | . . , X . . . . . |
$$ | . . . . . O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+
- Click Here To Show Diagram Code
[go]$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . . . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . a b . |
$$ | . . , X . . . . . |
$$ | . . . . . O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+[/go]
In the above diagram, thinking that a is sente because White must answer b is a mistake !... because then, Black must answer White b.
$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . a . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . 1 2 . |
$$ | . . , X . . 3 . . |
$$ | . . . . . O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+
- Click Here To Show Diagram Code
[go]$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . a . . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . 1 2 . |
$$ | . . , X . . 3 . . |
$$ | . . . . . O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+[/go]
Here, Black 3 is locally sente. But is it really sente ? White could ignore Black 3 and take a instead.
On the other hand, for me, a is really sente, because, in the diagram below, after move 2, black can stop there and play b
$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . 1 2 . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . b . . |
$$ | . . , X . . . . . |
$$ | . . . . c O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+
- Click Here To Show Diagram Code
[go]$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . 1 2 . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . b . . |
$$ | . . , X . . . . . |
$$ | . . . . c O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+[/go]
c is reverse sente, so it can be played next.
$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . 1 2 . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . 3 4 . |
$$ | . . , X . . 5 6 . |
$$ | . . . . 7 O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+
- Click Here To Show Diagram Code
[go]$$B
$$ +-------------------+
$$ | . . . . . . . . . |
$$ | . . . . 1 2 . . . |
$$ | . . , X . O , . . |
$$ | . . . X . O . . . |
$$ | . . X . , . O . . |
$$ | . . . . X . 3 4 . |
$$ | . . , X . . 5 6 . |
$$ | . . . . 7 O . O . |
$$ | . . . . . . . . . |
$$ +-------------------+[/go]
If you are counting continuations, when black and white continuations are both gote, you can assume that the continuation is halfway between them. If one of the continuations only is sente, assume that it will be the one being played.
Another trick : if you have prisoners that need to be counted in parallel, you can switch to area counting (just count the number of intersections that change colour if White starts instead of Black, stones included). I'm not sure of the implications. Robert Jasiek talks about it in his book Endgame 2, but I have not yet read this chapter.